08-05
28
Java获取完整URL
作者:Java伴侣 日期:2008-05-28
复制内容到剪贴板 程序代码
/**
* 格式化中文字符,防止出现乱码
* @param str
* @return
*/
public String codeToString(String str) {
String strString = str;
try {
byte tempB[] = strString.getBytes("ISO-8859-1");
strString = new String(tempB);
return strString;
} catch (Exception e) {
return strString;
}
}
/** *//**
* 获取完整的Url
* @param request
* @return
* @throws Exception
*/
public String getBackUrl(javax.servlet.http.HttpServletRequest request) throws Exception {
String strBackUrl = "";
try {
strBackUrl = "http://" + request.getServerName() + ":" + request.getServerPort() + request.getContextPath() + request.getServletPath() + "?" + this.codeToString(request.getQueryString());
strBackUrl = java.net.URLEncoder.encode(strBackUrl,"gbk");
} catch(Exception e) {
throw e;
}
return strBackUrl;
}
* 格式化中文字符,防止出现乱码
* @param str
* @return
*/
public String codeToString(String str) {
String strString = str;
try {
byte tempB[] = strString.getBytes("ISO-8859-1");
strString = new String(tempB);
return strString;
} catch (Exception e) {
return strString;
}
}
/** *//**
* 获取完整的Url
* @param request
* @return
* @throws Exception
*/
public String getBackUrl(javax.servlet.http.HttpServletRequest request) throws Exception {
String strBackUrl = "";
try {
strBackUrl = "http://" + request.getServerName() + ":" + request.getServerPort() + request.getContextPath() + request.getServletPath() + "?" + this.codeToString(request.getQueryString());
strBackUrl = java.net.URLEncoder.encode(strBackUrl,"gbk");
} catch(Exception e) {
throw e;
}
return strBackUrl;
}
评论: 0 | 引用: 0 | 查看次数: 1104
发表评论